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JEE Main 2025 (29 Jan, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2025 (29 Jan, Shift 2)

Q19JEE Main 2025 · 29 JAN · SHIFT 2Easy

Units & Dimensions

Match List - I with List - II.

Figure

Choose the correct answer from the options given below:

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Answer: (d)

  1. Young's modulus = stress/strain =[ML−1T−2]= [\mathrm{ML^{-1}T^{-2}}] → (II).
  2. Torque =rF=[ML2T−2]= rF = [\mathrm{ML^2T^{-2}}] → (IV).
  3. Viscosity =[ML−1T−1]= [\mathrm{ML^{-1}T^{-1}}] → (I).
  4. G=Fr2m2=[M−1L3T−2]G = \dfrac{Fr^2}{m^2} = [\mathrm{M^{-1}L^3T^{-2}}] → (III).
  5. So the answer is (d) A-II, B-IV, C-I, D-III.
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