Match List - I with List - II. Choose the correct answer from the options given below: (a) (A)-(III), (B)-(II), (C)-(I), (D)-(IV) (b) (A)-(II), (B)-(IV), (C)-(I), (D)-(III) (c) (A)-(IV), (B)-(II), (C)-(III), (D)-(I) (d) (A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Answer: (c). Isothermal: T constant ⇒ Δ U = 0: (A)-(IV). Adiabatic: no heat exchange, Δ Q = 0: (B)-(II). Isobaric: T changes, so Δ U ≠ 0: (C)-(III). Isochoric: V constant, so Δ W = 0: (D)-(I). So the answer is (c).

Match List - I with List - II. Choose the correct answer from the… | JEE Main 2025 (7 Apr, Shift 2)

Q56JEE Main 2025 · 7 APR · SHIFT 2Easy

Thermodynamic Processes

Match List - I with List - II.

Choose the correct answer from the options given below:

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Answer: (c)

Isothermal: $T$ constant $\Rightarrow \Delta U = 0$ : (A)-(IV).
Adiabatic: no heat exchange, $\Delta Q = 0$ : (B)-(II).
Isobaric: $T$ changes, so $\Delta U \neq 0$ : (C)-(III).
Isochoric: $V$ constant, so $\Delta W = 0$ : (D)-(I).
So the answer is (c).

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Thermodynamic Processes question from JEE Main 2025 (7 Apr, Shift 2)

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