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JEE Main 2026 (23 Jan, Shift 1) · Displacement Current, Maxwell's Equations & Production

Displacement Current, Maxwell's Equations & Production question from JEE Main 2026 (23 Jan, Shift 1)

Q1JEE Main 2026 · 23 JAN · SHIFT 1Easy

Displacement Current, Maxwell's Equations & Production

Match List - I with List - II.

Choose the correct answer from the options given below:

List - I RelationList - II Law
A. ∮E⃗⋅dl⃗=−ddt∮B⃗⋅da⃗\oint \vec{E} \cdot \vec{dl} = -\frac{d}{dt} \oint \vec{B} \cdot \vec{da}I. Ampere's circuital law
B. ∮B⃗⋅dl⃗=μ0(I+ϵ0dϕEdt)\oint \vec{B} \cdot \vec{dl} = \mu_0 \left(I + \epsilon_0 \frac{d\phi_E}{dt}\right)II. Faraday's laws of electromagnetic induction
C. ∮E⃗⋅da⃗=1ϵ0∫Vρ dV\oint \vec{E} \cdot \vec{da} = \frac{1}{\epsilon_0} \int_V \rho \, dVIII. Ampere - Maxwell law
D. ∮B⃗⋅dl⃗=μ0I\oint \vec{B} \cdot \vec{dl} = \mu_0 IIV. Gauss's law of electrostatics
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Answer: (b)

  1. A: line integral of E⃗\vec{E} equals −dϕB/dt-d\phi_B/dt is Faraday's law (II).
  2. B: μ0(I+ϵ0dϕE/dt)\mu_0(I + \epsilon_0 d\phi_E/dt) includes displacement current, Ampere-Maxwell law (III).
  3. C: closed-surface flux of E⃗\vec{E} equals enclosed charge/ϵ0/\epsilon_0, Gauss's law (IV).
  4. D: ∮B⃗⋅dl⃗=μ0I\oint \vec{B}\cdot\vec{dl} = \mu_0 I is Ampere's circuital law (I).
  5. So the answer is (b) A-II, B-III, C-IV, D-I.
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