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JEE Main 2026 (28 Jan, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2026 (28 Jan, Shift 2)

Q6JEE Main 2026 · 28 JAN · SHIFT 2Medium

Units & Dimensions

Match List - I with List - II.

Figure

Choose the correct answer from the options given below:

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Answer: (b)

  1. Viscosity =[ML−1T−1]= [\mathrm{ML^{-1}T^{-1}}] → IV.
  2. Surface tension =F/l=[ML0T−2]= F/l = [\mathrm{ML^0T^{-2}}] → III.
  3. Pressure =F/A=[ML−1T−2]= F/A = [\mathrm{ML^{-1}T^{-2}}] → I.
  4. Surface energy is an energy =[ML2T−2]= [\mathrm{ML^2T^{-2}}] → II.
  5. So the answer is (b) A-IV, B-III, C-I, D-II.
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