Match List - I with List - II Choose the correct answer from the options given below List - I List - II (a) Gravitational constant (G) (i) [L²T ⁻²] (b) Gravitational potential energy (ii) [M ⁻¹L³T ⁻²] (c) Gravitational potential (iii) [LT ⁻²] (d) Gravitational intensity (iv) [ML²T ⁻²] (a) (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii) (b) (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii) (c) (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i) (d) (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

Answer: (b). F = (Gm₁m₂)/(r²) ⇒ G = (Fr²)/(m₁m₂) = [M⁻¹L³T⁻²]: (a)-(ii). Potential energy is energy: [ML²T⁻²]: (b)-(iv). Potential V = U/m = [L²T⁻²]: (c)-(i). Intensity E = F/m = [LT⁻²]: (d)-(iii). So the answer is (b).

Match List - I with List - II Choose the correct answer from the… | NEET 2022 (Phase 1)

Q10NEET 2022 · PHASE 1Easy

Newton's Law of Gravitation

Match List - I with List - II

Choose the correct answer from the options given below

	List - I		List - II
(a)	Gravitational constant (G)	(i)	$[L^{2}T$ $^{-2}]$
(b)	Gravitational potential energy	(ii)	$[M$ $^{-1}L^{3}T$ $^{-2}]$
(c)	Gravitational potential	(iii)	$[LT$ $^{-2}]$
(d)	Gravitational intensity	(iv)	$[ML^{2}T$ $^{-2}]$

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Answer: (b)

$F = \frac{Gm_1m_2}{r^2} \Rightarrow G = \frac{Fr^2}{m_1m_2} = [M^{-1}L^3T^{-2}]$ : (a)-(ii).
Potential energy is energy: $[ML^2T^{-2}]$ : (b)-(iv).
Potential $V = U/m = [L^2T^{-2}]$ : (c)-(i).
Intensity $E = F/m = [LT^{-2}]$ : (d)-(iii).
So the answer is (b).

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