Match List I with List II: Choose the correct answer from the options given below: List I (Spectral Lines of Hydrogen for transitions from) List II (Wavelengths (nm)) A. n₂ = 3 to n₁ = 2 I. 410.2 B. n₂ = 4 to n₁ = 2 II. 434.1 C. n₂ = 5 to n₁ = 2 III. 656.3 D. n₂ = 6 to n₁ = 2 IV. 486.1 (a) A-II, B-I, C-IV, D-III (b) A-III, B-IV, C-II, D-I (c) A-IV, B-III, C-I, D-II (d) A-I, B-II, C-III, D-IV

Answer: (b). Larger energy gap means shorter wavelength, so λ decreases as n₂ increases for the Balmer lines. 3 → 2 ( Hα): 656.3 nm (III); 4 → 2 ( Hβ): 486.1 nm (IV) 5 → 2 ( Hγ): 434.1 nm (II); 6 → 2 ( Hδ): 410.2 nm (I) So the answer is (b) A-III, B-IV, C-II, D-I.

Match List I with List II: Choose the correct answer from the options… | NEET 2024

Q27NEET 2024Difficult

Hydrogen Spectrum & Spectral Series

Match List I with List II:

Choose the correct answer from the options given below:

	List I (Spectral Lines of Hydrogen for transitions from)		List II (Wavelengths (nm))
A.	$n_2 = 3$ to $n_1 = 2$	I.	410.2
B.	$n_2 = 4$ to $n_1 = 2$	II.	434.1
C.	$n_2 = 5$ to $n_1 = 2$	III.	656.3
D.	$n_2 = 6$ to $n_1 = 2$	IV.	486.1

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Answer: (b)

Larger energy gap means shorter wavelength, so $\lambda$ decreases as $n_2$ increases for the Balmer lines.
$3 \to 2$ ( $H_\alpha$ ): 656.3 nm (III); $4 \to 2$ ( $H_\beta$ ): 486.1 nm (IV)
$5 \to 2$ ( $H_\gamma$ ): 434.1 nm (II); $6 \to 2$ ( $H_\delta$ ): 410.2 nm (I)
So the answer is (b) A-III, B-IV, C-II, D-I.

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