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JEE Main 2025 (2 Apr, Shift 2) · Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Calorimetry, Latent Heat & Mechanical Equivalent of Heat question from JEE Main 2025 (2 Apr, Shift 2)

Q12JEE Main 2025 · 2 APR · SHIFT 2Easy

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Match List - I with List - II.

List - I List - II\text{List - II}

(A) Heat capacity of body (I) J kg−1\text{J kg}^{-1}

(B) Specific heat capacity of body (II) J K−1\text{J K}^{-1}

(C) Latent heat (III) J kg−1 K−1\text{J kg}^{-1}\text{ K}^{-1}

(D) Thermal conductivity (IV) J m−1 K−1 s−1\text{J m}^{-1}\text{ K}^{-1}\text{ s}^{-1}

Choose the correct answer from the options given below:

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Answer: (d)

  1. (A) Heat capacity =Q/ΔT⇒J K−1= Q/\Delta T \Rightarrow \text{J K}^{-1} (II).
  2. (B) Specific heat =Q/(mΔT)⇒J kg−1K−1= Q/(m\Delta T) \Rightarrow \text{J kg}^{-1}\text{K}^{-1} (III).
  3. (C) Latent heat =Q/m⇒J kg−1= Q/m \Rightarrow \text{J kg}^{-1} (I).
  4. (D) Thermal conductivity K=Q xA ΔT t⇒J m−1K−1s−1K = \dfrac{Q\,x}{A\,\Delta T\,t} \Rightarrow \text{J m}^{-1}\text{K}^{-1}\text{s}^{-1} (IV).
  5. So the answer is (d) (A)-(II), (B)-(III), (C)-(I), (D)-(IV).
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