Match List I with List II: (Where a = radius of planet orbit, r = radius of planet, M = mass of Sun, m = mass of planet) Choose the correct answer from the options given below: LIST I LIST II A. Kinetic energy of planet I. - GMm/a B. Gravitation Potential energy of sun-planet system II. GMm/2a C. Total mechanical energy of planet III. Gm/r D. Escape energy at the surface of planet for unit mass object IV. - GMm/2a (a) (A)-(II), (B)-(I), (C)-(IV), (D)-(III) (b) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (c) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) (d) (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

Answer: (a). A: kinetic energy = GMm/2a (II). B: potential energy = -GMm/a (I). C: total energy = -GMm/2a (IV). D: escape energy per unit mass at the planet's surface = Gm/r (III). So the answer is (a) A-II, B-I, C-IV, D-III.

Match List I with List II: (Where a = radius of planet orbit, r =… | JEE Main 2024 (5 Apr, Shift 1)

Q8JEE Main 2024 · 5 APR · SHIFT 1Medium

Satellite Energy & Weightlessness

Match List I with List II:

(Where $a =$ radius of planet orbit, $r =$ radius of planet, $M =$ mass of Sun, $m =$ mass of planet)

Choose the correct answer from the options given below:

	LIST I		LIST II
A.	Kinetic energy of planet	I.	$-$ $GMm/a$
B.	Gravitation Potential energy of sun-planet system	II.	$GMm/2a$
C.	Total mechanical energy of planet	III.	$\frac{Gm}{r}$ $\,$
D.	Escape energy at the surface of planet for unit mass object	IV.	$-$ $GMm/2a$

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Answer: (a)

A: kinetic energy $= \frac{GMm}{2a}$ (II).
B: potential energy $= -\frac{GMm}{a}$ (I).
C: total energy $= -\frac{GMm}{2a}$ (IV).
D: escape energy per unit mass at the planet's surface $= \frac{Gm}{r}$ (III).
So the answer is (a) A-II, B-I, C-IV, D-III.

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Satellite Energy & Weightlessness question from JEE Main 2024 (5 Apr, Shift 1)

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