Applications of Dimensional Analysis question from JEE Main 2026 (5 Apr, Shift 2)

Answer: (b)

1. Planck length $= \sqrt{\frac{Gh}{c^{3}}}$, so A-IV.
2. Planck time $= \sqrt{\frac{Gh}{c^{5}}}$, so B-II.
3. Planck mass $= \sqrt{\frac{hc}{G}}$, so C-I; the remaining temperature expression gives D-III.
4. So the answer is (b) A-IV, B-II, C-I, D-III.