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NEET 2016 (Phase 1) · Reflection & Mirrors

Reflection & Mirrors question from NEET 2016 (Phase 1)

Q47NEET 2016 · PHASE 1Easy

Reflection & Mirrors

Match the corresponding entries of column 1 with column 2. [Where m is the magnification

produced by the mirror]

Figure

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Answer: (c)

  1. Negative mm: inverted, real image, formed only by a concave mirror. So A (−2-2) and B (−12-\frac{1}{2}) →\to q, r.
  2. m=+2m = +2: erect and magnified, only a concave mirror (object inside FF), virtual. C →\to q, s.
  3. m=+12m = +\frac{1}{2}: erect and diminished, convex mirror, virtual. D →\to p, s.
  4. So the answer is (c).
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