Match the (CP)/(CV) ratio for ideal gases with different type of molecules: (a) (A)-(III), (B)-(IV), (C)-(II), (D)-(I) (b) (A)-(IV), (B)-(II), (C)-(I), (D)-(III) (c) (A)-(IV), (B)-(I), (C)-(II), (D)-(III) (d) (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Answer: (c). Monatomic: f = 3, γ = 1 + 2/3 = 5/3 → (IV). Diatomic rigid: f = 5, γ = 7/5 → (I). Diatomic non-rigid (one vibrational mode): CV = 7/2R, γ = 9/7 → (II). Triatomic rigid (non-linear): f = 6, γ = 1 + 2/6 = 4/3 → (III). So the answer is (c) (A)-(IV), (B)-(I), (C)-(II), (D)-(III).

Match the (CP)/(CV) ratio for ideal gases with different type of… | JEE Main 2020 (4 Sep, Shift 1)

Q45JEE Main 2020 · 4 SEP · SHIFT 1Medium

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Match the $\frac{C_P}{C_V}$ ratio for ideal gases with different type of molecules:

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Answer: (c)

Monatomic: $f = 3$ , $\gamma = 1 + \dfrac{2}{3} = \dfrac{5}{3}$ → (IV).
Diatomic rigid: $f = 5$ , $\gamma = \dfrac{7}{5}$ → (I).
Diatomic non-rigid (one vibrational mode): $C_V = \dfrac{7}{2}R$ , $\gamma = \dfrac{9}{7}$ → (II).
Triatomic rigid (non-linear): $f = 6$ , $\gamma = 1 + \dfrac{2}{6} = \dfrac{4}{3}$ → (III).
So the answer is (c) (A)-(IV), (B)-(I), (C)-(II), (D)-(III).

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from JEE Main 2020 (4 Sep, Shift 1)

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