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MHT CET 2026 (14 May, Shift 1) · Energy in SHM

Energy in SHM question from MHT CET 2026 (14 May, Shift 1)

Q12MHT CET 2026 · 14 MAY · SHIFT 1Medium

Energy in SHM

Maximum kinetic energy of a particle of mass 11 kg in S.H.M. is 88 J and the time period is 44 s. Maximum potential energy during the motion is 1010 J. Then

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Answer: (c)

  1. ω=2πT=π2\omega = \frac{2\pi}{T} = \frac{\pi}{2} rad/s; PE has a constant offset: PEmin=10−8=2PE_{min} = 10 - 8 = 2 J, so (b) is false.
  2. Minimum KE is 0 at the extremes, so (d) is false.
  3. 12mω2A2=8⇒A2=16π2/4=64π2\frac{1}{2}m\omega^2A^2 = 8 \Rightarrow A^2 = \frac{16}{\pi^2/4} = \frac{64}{\pi^2}, A=8π≈2.55A = \frac{8}{\pi} \approx 2.55 m, so (a) is false.
  4. amax=ω2A=π24×8π=2πa_{max} = \omega^2A = \frac{\pi^2}{4} \times \frac{8}{\pi} = 2\pi m/s2^2
  5. So the answer is (c).
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