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JEE Main 2019 (9 Jan, Shift 1) · Intrinsic & Extrinsic Semiconductors

Intrinsic & Extrinsic Semiconductors question from JEE Main 2019 (9 Jan, Shift 1)

Q46JEE Main 2019 · 9 JAN · SHIFT 1Medium

Intrinsic & Extrinsic Semiconductors

Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If, for an n-type semiconductor, the density of electrons is 1019 m−3{}^{-3} and their mobility is 1.6 m2/(V.s) then the resistivity of the semiconductor (since it is an n-type semiconductor contribution of holes is ignored) is close to:

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Answer: (c)

  1. For an n-type semiconductor, σ=neμe\sigma = n e \mu_e and ρ=1neμe\rho = \dfrac{1}{n e \mu_e}.
  2. ρ=11019×1.6×10−19×1.6=12.56\rho = \dfrac{1}{10^{19} \times 1.6 \times 10^{-19} \times 1.6} = \dfrac{1}{2.56}
  3. ρ≈0.39 Ω m\rho \approx 0.39\ \Omega\,\text{m}
  4. So the answer is (c) 0.4 Ω m0.4\ \Omega\,\text{m}.
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