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JEE Main 2020 (3 Sep, Shift 1) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2020 (3 Sep, Shift 1)

Q42JEE Main 2020 · 3 SEP · SHIFT 1Difficult

Ohm's Law, Resistivity & Temperature

Model a torch battery of length ll to be made up of a thin cylindrical bar of radius ‘a’ and a concentric thin cylindrical shell of radius ‘b’ filled in between with an electrolyte of resistivity ρ\rho (see figure). If the battery is connected to a resistance of value R, the maximum Joule heating in R will take place for:

Figure

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Answer: (c)

  1. Internal resistance: current flows radially through shells of area 2πrl2\pi r l, so rint=∫abρ dr2πrl=ρ2πlln⁡bar_{int} = \int_a^b \dfrac{\rho\,dr}{2\pi r l} = \dfrac{\rho}{2\pi l}\ln\dfrac{b}{a}.
  2. Power in RR is maximum when R=rintR = r_{int} (maximum power transfer).
  3. R=ρ2πlln⁡baR = \dfrac{\rho}{2\pi l}\ln\dfrac{b}{a}. The answer is (c).
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