Student Login

Home›Chapters›Thermodynamics PYQs›Degrees of Freedom & Internal Energy›Question 28

JEE Main 2020 (6 Sep, Shift 1) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from JEE Main 2020 (6 Sep, Shift 1)

Q28JEE Main 2020 · 6 SEP · SHIFT 1Easy

Degrees of Freedom & Internal Energy

Molecules of an ideal gas are known to have three translational degrees of freedom and two rotational degrees of freedom.The gas is maintained at a temperature of T. The total internal energy, U of a mole of this gas, and the value of

$\gamma\left(=\frac{C_p}{C_v}\right)$ are given, respectively by:

Show answer and solution

Answer: (a)

$f = 3 + 2 = 5$ , so for one mole $U = \frac{f}{2}RT = \frac{5}{2}RT$ .
$\gamma = 1 + \frac{2}{f} = 1 + \frac{2}{5} = \frac{7}{5}$
So the answer is (a).

Report a mistake

More questions on Degrees of Freedom & Internal Energy

Consider a gas of triatomic molecules. The molecules are assumed to be triangular and…JEE Main 2020 (3 Sep, Shift 1)
A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T…JEE Main 2020 (2 Sep, Shift 1)
A closed vessel contains 0.1 mole of a monoatomic ideal gas at 200 K. If 0.05 mole of the…JEE Main 2020 (4 Sep, Shift 1)
Initially a gas of diatomic molecules is contained in a cylinder of volume V1 at a…JEE Main 2020 (6 Sep, Shift 1)
A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T…JEE Main 2019 (11 Jan, Shift 1)
Two kg of a monoatomic gas is at a pressure of 4 × 104 N/m2. The density of the gas is 8…JEE Main 2019 (10 Jan, Shift 2)
A gas mixture consists of 2 moles of O2 and 4 moles of Ar at temperature T. Neglecting…NEET 2017
N moles of a diatomic gas in a cylinder are at a temperature T. Heat is supplied to the…JEE Main 2017 (9 Apr, Shift 1)