Moment of inertia (M. I.) of four bodies, having same mass and… | JEE Main 2021 (24 Feb, Shift 1)

Q131JEE Main 2021 · 24 FEB · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Moment of inertia (M. I.) of four bodies, having same mass and radius, are reported as; I1 = M.I. of thin circular ring about its diameter,

I2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre, I3 = M.I. of solid cylinder about its axis and

I4 = M.I. of solid sphere about its diameter.

Then:

Show answer and solution

Answer: (a)

$I_1$ (ring, diameter) $= \frac{1}{2}MR^2$ ; $I_2$ (disc, perpendicular axis) $= \frac{1}{2}MR^2$ .
$I_3$ (solid cylinder, own axis) $= \frac{1}{2}MR^2$ ; $I_4$ (solid sphere, diameter) $= \frac{2}{5}MR^2$ .
So the answer is (a) $I_1 = I_2 = I_3 > I_4$ .

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