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JEE Main 2002 (AIEEE) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from JEE Main 2002 (AIEEE)

Q198JEE Main 2002 · AIEEEEasy

Moment of Inertia & Radius of Gyration

Moment of inertia of a circular wire of mass $M$ and radius $R$ about its diameter is

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Answer: (a)

Ring about its central perpendicular axis: $I_z = MR^2$ .
Perpendicular axis theorem: $I_z = I_{d} + I_{d} = 2I_d$ (two equal diameters).
$I_d = \frac{MR^2}{2}$
So the answer is (a) $\frac{MR^2}{2}$ .

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