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MHT CET 2025 (26 Apr, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2025 (26 Apr, Shift 1)

Q49MHT CET 2025 · 26 APR · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Moment of inertia of a solid sphere about its diameter is 'I'. It is then casted into 27 small spheres of same diameter. The moment of inertia of each small sphere about its diameter is

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Answer: (d)

  1. Each small sphere: mass M27\frac{M}{27}, radius R3\frac{R}{3} (volume shares 1/27).
  2. I′=25⋅M27⋅R29=I243I' = \frac{2}{5}\cdot\frac{M}{27}\cdot\frac{R^2}{9} = \frac{I}{243}
  3. So the answer is (d) I243\frac{I}{243}.
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