Motion of a particle in x-y plane is described by a set of following equations x = 4sin (π/2-ω t) m and y = 4sin (ω t) m. The path of the particle will be: (a) circular (b) helical (c) parabolic (d) elliptical

Answer: (a). x = 4sin (π/2 - ω t) = 4cos ω t, y = 4sin ω t. x² + y² = 16: a circle of radius 4 m, answer (a).

Motion of a particle in x-y plane is described by a set of following… | JEE Main 2022 (28 Jun, Shift 1)

Q5JEE Main 2022 · 28 JUN · SHIFT 1Easy

Damped, Forced Oscillations & Superposition

Motion of a particle in x-y plane is described by a set of following equations $x = 4\sin\left(\frac{\pi}{2}-\omega t\right)\text{ m}$ and $y = 4\sin(\omega t)\text{ m}$ . The path of the particle will be:

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Answer: (a)

$x = 4\sin\left(\frac{\pi}{2} - \omega t\right) = 4\cos\omega t$ , $y = 4\sin\omega t$ .
$x^2 + y^2 = 16$ : a circle of radius 4 m, answer (a).

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Damped, Forced Oscillations & Superposition question from JEE Main 2022 (28 Jun, Shift 1)

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