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JEE Main 2019 (10 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2019 (10 Apr, Shift 1)

Q216JEE Main 2019 · 10 APR · SHIFT 1Medium

Thermodynamic Processes

n moles of an ideal gas with constant volume heat capcity CV undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is:

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Answer: (d)

Here $C_V$ is the heat capacity of the whole gas, so $Q = (C_V + nR)\Delta T$ at constant pressure.
$W = P\Delta V = nR\Delta T$
$\frac{W}{Q} = \frac{nR}{C_V + nR}$
So the answer is (d) $\frac{nR}{C_V + nR}$ .

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