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MHT CET 2026 (12 May, Shift 2) · Terminal Velocity

Terminal Velocity question from MHT CET 2026 (12 May, Shift 2)

Q3MHT CET 2026 · 12 MAY · SHIFT 2Easy

Terminal Velocity

$'n'$ small drops of water having same size fall through air with constant velocity $4$ cm/s. They coalesce to form a big drop. The terminal velocity of the big drop is

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Answer: (c)

Terminal velocity $v = \dfrac{2r^2(\rho-\sigma)g}{9\eta}$ , so $v \propto r^2$ .
Volume is conserved: $\frac{4}{3}\pi R^3 = n\cdot\frac{4}{3}\pi r^3 \Rightarrow R = n^{1/3}r$ .
$v' = v\left(\frac{R}{r}\right)^2 = 4n^{2/3}$ cm/s
So the answer is (c) $4n^{2/3}$ cm/s.

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