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JEE Main 2022 (24 Jun, Shift 1) · Nuclear Fission & Fusion

Nuclear Fission & Fusion question from JEE Main 2022 (24 Jun, Shift 1)

Q18JEE Main 2022 · 24 JUN · SHIFT 1Easy

Nuclear Fission & Fusion

Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits into two fragments 'B' and 'C' of mass numbers 105 and 115. The binding energy of nucleons in 'B' and 'C' is 6.4 MeV per nucleon. The energy Q released per fission will be:

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Answer: (d)

  1. Q=Q = BE of fragments −- BE of parent =220×6.4−220×5.6= 220 \times 6.4 - 220 \times 5.6 (since 105+115=220105 + 115 = 220).
  2. Q=220×0.8=176 MeVQ = 220 \times 0.8 = 176\ \text{MeV}
  3. So the answer is (d) 176 MeV176\ \text{MeV}.
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