On a photosensitive surface, if the intensity of incident radiation is increased, the stopping potential (a) first increases and then decreases (b) decreases (c) increases (d) remains unchanged

Answer: (d). eV₀ = hν - φ contains no intensity term. Higher intensity only gives more electrons, each with the same Kmax. So the answer is (d) remains unchanged.

On a photosensitive surface, if the intensity of incident radiation… | MHT CET 2021 (21 Sep, Shift 1)

Q51MHT CET 2021 · 21 SEP · SHIFT 1Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

On a photosensitive surface, if the intensity of incident radiation is increased, the stopping potential

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Answer: (d)

$eV_0 = h\nu - \phi$ contains no intensity term.
Higher intensity only gives more electrons, each with the same $K_{max}$ .
So the answer is (d) remains unchanged.

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2021 (21 Sep, Shift 1)

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