On an imaginary linear scale of temperature (called 'W' scale) the freezing and boiling points of water are 39 ° W and 239 ° W respectively. The temperature on the new scale corresponding to 39 ° C temperature on Celsius scale will be (a) 139 ° W (b) 78 ° W (c) 117 ° W (d) 200 ° W

Answer: (c). (W-39)/(239-39)=(C-0)/(100), so W=39+2C. W=39+2× 39=117 So the answer is (c) 117° W.

On an imaginary linear scale of temperature (called 'W' scale) the… | MHT CET 2021 (20 Sep, Shift 1)

Q47MHT CET 2021 · 20 SEP · SHIFT 1Easy

Thermometry & Thermal Expansion

On an imaginary linear scale of temperature (called 'W' scale) the freezing and boiling points of water are 39 $^\circ$ W and 239 $^\circ$ W respectively. The temperature on the new scale corresponding to 39 $^\circ$ C temperature on Celsius scale will be

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Answer: (c)

$\frac{W-39}{239-39}=\frac{C-0}{100}$ , so $W=39+2C$ .
$W=39+2\times 39=117$
So the answer is (c) $117^\circ$ W.

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Thermometry & Thermal Expansion question from MHT CET 2021 (20 Sep, Shift 1)

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