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JEE Main 2024 (4 Apr, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from JEE Main 2024 (4 Apr, Shift 1)

Q22JEE Main 2024 · 4 APR · SHIFT 1Easy

Thermometry & Thermal Expansion

On Celsius scale the temperature of body increases by 40∘C40^\circ\text{C}. The increase in temperature on Fahrenheit scale is:

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Answer: (c)

  1. ΔF=95ΔC\Delta F=\frac{9}{5}\Delta C
  2. ΔF=95×40=72\Delta F=\frac{9}{5}\times 40=72
  3. So the answer is (c) 72∘72^\circF.
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