On dry road, the maximum speed of a vehicle along a circular path is ' V '. When the road becomes wet, maximum speed becomes V/2. If coefficient of friction of dry road is ' μ ' then that of wet road is (a) 2μ/3 (b) μ/4 (c) μ/3 (d) 3μ/4

Answer: (b). On a level road vmax = √(μ r g), so μ ∝ v². (μ')/(μ) = (V/2/V)² = 1/4 So the answer is (b) μ/4.

On dry road, the maximum speed of a vehicle along a circular path is… | MHT CET 2023 (14 May, Shift 1)

Q6MHT CET 2023 · 14 MAY · SHIFT 1Easy

Level Road & Rotating Platform

On dry road, the maximum speed of a vehicle along a circular path is ' $V$ '. When the road becomes wet, maximum speed becomes $\frac{V}{2}$ . If coefficient of friction of dry road is ' $\mu$ ' then that of wet road is

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Answer: (b)

On a level road $v_{max} = \sqrt{\mu r g}$ , so $\mu \propto v^2$ .
$\frac{\mu'}{\mu} = \left(\frac{V/2}{V}\right)^2 = \frac{1}{4}$
So the answer is (b) $\frac{\mu}{4}$ .

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