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NEET 2001 (AIPMT) · Friction Basics

Friction Basics question from NEET 2001 (AIPMT)

Q37NEET 2001 · AIPMTMedium

Friction Basics

On the horizontal surface of a truck a block of mass 1 kg is placed (μ\mu = 0.6) and truck is moving with acceleration 5 m/sec2 then the frictional force on the block will be

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Answer: (a)

  1. To move with the truck the block needs f=ma=1×5=5 Nf = ma = 1 \times 5 = 5\text{ N}.
  2. Maximum static friction μmg=0.6×1×9.8=5.88 N>5 N\mu mg = 0.6 \times 1 \times 9.8 = 5.88\text{ N} > 5\text{ N}, so the block does not slip.
  3. Static friction only supplies what is needed: f=5 Nf = 5\text{ N}.
  4. So the answer is (a) 5 N.
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