Physics Circle home Student Login

Home›Chapters›Laws of Motion PYQs›Apparent Weight & Lift›Question 24

JEE Main 2002 (AIEEE) · Apparent Weight & Lift

Apparent Weight & Lift question from JEE Main 2002 (AIEEE)

Q24JEE Main 2002 · AIEEEEasy

Apparent Weight & Lift

One end of a mass-less rope, which passes over a mass-less and friction-less pulley PP is tied to a hook CC while the other end is free. Maximum tension that the rope can bear is 360 N.360\text{ N}. With what value of maximum safe acceleration (in ms−2\text{ms}^{-2}) can a man of 60 kg60\text{ kg} climb on the rope?

Figure

Show answer and solution

Answer: (c)

  1. Tension cannot exceed 360 N, which is less than the man's weight mg=600mg = 600 N.
  2. So the man can hold on only while accelerating downward: mg−T=mamg - T = ma.
  3. a=600−36060=4 m s−2a = \frac{600 - 360}{60} = 4\text{ m s}^{-2} (downward)
  4. So the answer is (c) 44.
Report a mistake

More questions on Apparent Weight & Lift