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MHT CET 2026 (19 Apr, Shift 1) · Surface Energy & Work Done

Surface Energy & Work Done question from MHT CET 2026 (19 Apr, Shift 1)

Q3MHT CET 2026 · 19 APR · SHIFT 1Medium

Surface Energy & Work Done

One large soap bubble of diameter 'D' breaks into $64$ bubbles having surface tension 'T'. The change in surface energy is

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Answer: (c)

Surface energy of a bubble $= 8\pi r^2 T$ . Big bubble radius $R = D/2$ : $E_1 = 8\pi (D/2)^2 T = 2\pi T D^2$ .
Volume conserved: $64 r^3 = R^3 \Rightarrow r = R/4 = D/8$ .
$E_2 = 64 \times 8\pi (D/8)^2 T = 8\pi T D^2$
$\Delta E = 8\pi TD^2 - 2\pi TD^2 = 6\pi TD^2$
So the answer is (c) $6\pi TD^2$ .

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