One main scale division of a Vernier calliper is equal to 1 mm and… | NEET 2026 (Re-neet)

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Least Count, Vernier Callipers & Screw Gauge

One main scale division of a Vernier calliper is equal to 1 mm and the number of divisions on the Vernier scale is 10. When both the jaws touch each other, the Vernier scale shifts to the left of zero of the main scale in such a way that $4$ th Vernier division coincides with a division of the main scale. If this Vernier calliper measures the length of the wire to be 1 cm, the actual length of the wire is:

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Answer: (a)

LC $= \dfrac{1\text{ mm}}{10} = 0.1$ mm $= 0.01$ cm
Vernier zero to the left of main zero means negative zero error; taking it as $4\times\text{LC}$ : $e = -0.04$ cm.
True length $= \text{reading} - e = 1 - (-0.04) = 1.04$ cm
So the answer is (a) $1.04$ cm.

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