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JEE Main 2014 · P-V Diagrams & Cyclic Processes

P-V Diagrams & Cyclic Processes question from JEE Main 2014

Q75JEE Main 2014Difficult

P-V Diagrams & Cyclic Processes

One mole of a diatomic ideal gas undergoes a cyclic process ABCABC as shown in figure. The process BCBC is adiabatic. The temperatures at A,BA, B and CC are 400 K, 800 K400\text{ K},\ 800\text{ K} and 600 K600\text{ K} respectively. Choose the correct statement:

Figure

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Answer: (d)

  1. For 1 mol of diatomic gas, ΔU=CvΔT=52R ΔT\Delta U = C_v\Delta T = \frac{5}{2}R\,\Delta T
  2. ABAB: ΔU=52R(800−400)=1000R\Delta U = \frac{5}{2}R(800 - 400) = 1000R
  3. BCBC: ΔU=52R(600−800)=−500R\Delta U = \frac{5}{2}R(600 - 800) = -500R
  4. CACA: ΔU=52R(400−600)=−500R\Delta U = \frac{5}{2}R(400 - 600) = -500R; whole cycle: ΔU=0\Delta U = 0
  5. So the answer is (d) ΔUBC=−500R\Delta U_{BC} = -500R.
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