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NEET 2004 (AIPMT) · Thermodynamic Processes

Thermodynamic Processes question from NEET 2004 (AIPMT)

Q245NEET 2004 · AIPMTMedium

Thermodynamic Processes

One mole of an ideal gas at an initial temperature of T K does 6R joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be

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Answer: (d)

Adiabatic work by gas: $W = \frac{nR(T_1 - T_2)}{\gamma - 1}$ , with $n = 1$ , $\gamma - 1 = \frac{2}{3}$ .
$6R = \frac{3}{2}R(T - T_2) \Rightarrow T - T_2 = 4$
So the answer is (d) $(T - 4)$ K.

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