Student Login

Home›Chapters›Thermodynamics PYQs›Thermodynamic Processes›Question 255

NEET 1990 (AIPMT) · Thermodynamic Processes

Thermodynamic Processes question from NEET 1990 (AIPMT)

Q255NEET 1990 · AIPMTMedium

Thermodynamic Processes

One mole of an ideal gas requires 207 J heat to rise the temperature by 10 K when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by the same 10 K, the heat required is

(Given the gas constant $R = 8.3\text{ J/mole K}$ )

Show answer and solution

Answer: (d)

$Q_p - Q_v = n(C_p - C_v)\Delta T = nR\Delta T$
$nR\Delta T = 1 \times 8.3 \times 10 = 83\text{ J}$
$Q_v = 207 - 83 = 124\text{ J}$
So the answer is (d) $124\text{ J}$ .

Report a mistake

More questions on Thermodynamic Processes

We consider a thermodynamic system. If Δ U is the increase in internal energy and W is…MHT CET 2026 (15 May, Shift 1)
Out of the following relations which one is true in the case of an adiabatic process…MHT CET 2026 (13 May, Shift 1)
The thermodynamic process in which no work is done by the gas or on the gas isMHT CET 2026 (19 Apr, Shift 1)
When the temperature of 4 moles of a gas was increased from 70° C to 90° C, at constant…MHT CET 2026 (19 May, Shift 1)
In thermodynamic isobaric processMHT CET 2026 (15 Apr, Shift 1)
Heat is supplied to a diatomic gas at constant pressure. Then the ratio of Δ Q: Δ U: Δ W…JEE Main 2026 (2 Apr, Shift 1)
If a gas is compressed isothermally then the r.m.s. velocity of the moleculesMHT CET 2026 (16 Apr, Shift 2)
A thermodynamic system is compressed adiabatically, then its temperatureMHT CET 2026 (17 Apr, Shift 2)