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JEE Main 2018 (15 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2018 (15 Apr, Shift 1)

Q220JEE Main 2018 · 15 APR · SHIFT 1Easy

Thermodynamic Processes

One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, $27^\circ\text{C}.$ The work done on the gas will be:

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Answer: (c)

Isothermal: $W_{on} = nRT\ln\frac{P_2}{P_1}$ .
$n = 1$ , $T = 300$ K, $\frac{P_2}{P_1} = 2$
$W_{on} = 300R\ln 2$
So the answer is (c) $300R\ln 2$ .

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