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MHT CET 2024 (16 May, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2024 (16 May, Shift 1)

Q18MHT CET 2024 · 16 MAY · SHIFT 1Easy

Refraction, Glass Slab & Apparent Depth

Optical path of a particular ray of light has travelled a distance of 3 cm in flint glass is same as that on travelling a distance ' $x$ ' cm through another medium. The value of ' $x$ ' is [refractive index of flint glass $= 1.6$ , refractive index of another medium $= 1.25]$

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Answer: (a)

Optical path $= \mu \times$ geometric path; equate them.
$1.6 \times 3 = 1.25 \times x$
$x = \frac{4.8}{1.25} = 3.84\text{ cm}$ . So the answer is (a).

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