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JEE Main 2020 (4 Sep, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from JEE Main 2020 (4 Sep, Shift 2)

Q67JEE Main 2020 · 4 SEP · SHIFT 2Medium

Diffraction at a Single Slit

Orange light of wavelength 6000 ×\times 10–10 m illuminates a single

slit of width 0.6 ×\times 10–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 200

  1. Minima: asin⁡θ=nλa\sin\theta = n\lambda, and sin⁡θ≤1\sin\theta \le 1, so n≤aλn \le \dfrac{a}{\lambda}.
  2. aλ=0.6×10−46×10−7=100\dfrac{a}{\lambda} = \dfrac{0.6 \times 10^{-4}}{6 \times 10^{-7}} = 100
  3. 100 minima on each side, so total =2×100=200= 2 \times 100 = 200.
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