P and Q are two non-zero vectors inclined to each other at an angle ' θ '. ' p ' and ' q ' are unit vectors along P and Q respectively. The component of Q in the direction of P will be (a) p · Q (b) (P × Q)/(P) (c) (P · Q)/(Q) (d) p · q

Answer: (a). Component of Q along P = Qcos θ. p · Q = (1)(Q)cos θ = Qcos θ since p is a unit vector along P. So the answer is (a) p · Q.

P and Q are two non-zero vectors inclined to each other at an angle '… | MHT CET 2019 (2 May, Shift 2)

Q22MHT CET 2019 · 2 MAY · SHIFT 2Easy

Scalar (Dot) Product

$\mathbf{P}$ and $\mathbf{Q}$ are two non-zero vectors inclined to each other at an angle ' $\theta$ '. ' $p$ ' and ' $q$ ' are unit vectors along $\mathbf{P}$ and $\mathbf{Q}$ respectively. The component of $\mathbf{Q}$ in the direction of $\mathbf{P}$ will be

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Answer: (a)

Component of $\mathbf{Q}$ along $\mathbf{P}$ $= Q\cos\theta$ .
$p \cdot Q = (1)(Q)\cos\theta = Q\cos\theta$ since $p$ is a unit vector along $\mathbf{P}$ .
So the answer is (a) $p \cdot Q$ .

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Scalar (Dot) Product question from MHT CET 2019 (2 May, Shift 2)

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