Photoelectric emission takes place from a certain metal at threshold frequency ν. If the radiation of frequency 4ν is incident on the metal plate, the maximum velocity of the emitted photoelectrons will be ( m = mass of photoelectron, h = Planck's constant) (a) √((6hν)/(m)) (b) √((3hν)/(m)) (c) √(hν/m) (d) √((5hν)/(m))

Answer: (a). 1/2mvmax² = h(4ν) - hν = 3hν vmax = √((6hν)/(m)) So the answer is (a) √((6hν)/(m)).

Photoelectric emission takes place from a certain metal at threshold… | MHT CET 2025 (22 Apr, Shift 2)

Q37MHT CET 2025 · 22 APR · SHIFT 2Easy

Photoelectric Effect: Einstein's Equation

Photoelectric emission takes place from a certain metal at threshold frequency $\nu$ . If the radiation of frequency $4\nu$ is incident on the metal plate, the maximum velocity of the emitted photoelectrons will be ( $m =$ mass of photoelectron, $h =$ Planck's constant)

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Answer: (a)

$\frac{1}{2}mv_{max}^2 = h(4\nu) - h\nu = 3h\nu$
$v_{max} = \sqrt{\frac{6h\nu}{m}}$
So the answer is (a) $\sqrt{\frac{6h\nu}{m}}$ .

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