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NEET 2016 (Phase 2) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from NEET 2016 (Phase 2)

Q140NEET 2016 · PHASE 2Medium

Photoelectric Effect: Einstein's Equation

Photons with energy 5 eV are incident on a cathode C in a photoelectric cell. The maximum energy of emitted photoelectrons is 2 eV. When photons of energy 6 eV are incident on C, no photoelectrons will reach the anode A, if the stopping potential of A relative to C is

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Answer: (d)

  1. ϕ=E−Kmax=5−2=3\phi = E - K_{max} = 5 - 2 = 3 eV
  2. For 6 eV photons: Kmax=6−3=3K_{max} = 6 - 3 = 3 eV
  3. To stop them the anode must be 3 V below the cathode: VA=−3V_A = -3 V
  4. So the answer is (d) −3-3 V.
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