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JEE Main 2024 (27 Jan, Shift 1) · Motion in a Plane (2-D Kinematics)

Motion in a Plane (2-D Kinematics) question from JEE Main 2024 (27 Jan, Shift 1)

Q2JEE Main 2024 · 27 JAN · SHIFT 1Easy

Motion in a Plane (2-D Kinematics)

Position of an ant ( $\text{S}$ in metres) moving in $\text{Y-Z}$ plane is given by $S = 2t^{2}\hat{j} + 5\hat{k}$ (where $t$ is in second). The magnitude and direction of velocity of the ant at $t = 1\text{ s}$ will be:

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Answer: (d)

$\vec v = \frac{d\vec S}{dt} = 4t\,\hat j$ (the $5\hat k$ term is constant)
At $t = 1$ s, $\vec v = 4\hat j$ m/s
So the answer is (d) 4 m/s in $y$ -direction.

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