Potential difference between the points A and B is nearly (a) 10 V (b) 14 V (c) 18 V (d) 20 V

Answer: (c). 8/4 = 10/5, so the bridge is balanced and no current flows through G. Branch ABC has 8 + 4 = 12 Ω, branch ADC has 10 + 5 = 15 Ω, in parallel. Current in ABC: I₁ = 4 × (15)/(12 + 15) = 20/9 A VA - VB = 8 × 20/9 ≈ 17.8 V ≈ 18 V So the answer is (c) 18 V.

Potential difference between the points A and B is nearly | MHT CET 2024 (9 May, Shift 2)

Q56MHT CET 2024 · 9 MAY · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

Potential difference between the points A and B is nearly

Show answer and solution

Answer: (c)

$\frac{8}{4} = \frac{10}{5}$ , so the bridge is balanced and no current flows through G.
Branch ABC has $8 + 4 = 12\ \Omega$ , branch ADC has $10 + 5 = 15\ \Omega$ , in parallel.
Current in ABC: $I_1 = 4 \times \frac{15}{12 + 15} = \frac{20}{9}\text{ A}$
$V_A - V_B = 8 \times \frac{20}{9} \approx 17.8\text{ V} \approx 18\text{ V}$
So the answer is (c) 18 V.

Report a mistake

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2024 (9 May, Shift 2)

More questions on Kirchhoff's Laws & Measuring Instruments