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JEE Main 2022 (24 Jun, Shift 2) · Potential Energy & Equilibrium

Potential Energy & Equilibrium question from JEE Main 2022 (24 Jun, Shift 2)

Q6JEE Main 2022 · 24 JUN · SHIFT 2Medium

Potential Energy & Equilibrium

Potential energy as a function of r is given by $U = \frac{A}{r^{10}} - \frac{B}{r^5}$ , where r is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be:

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Answer: (c)

$\frac{dU}{dr} = -\frac{10A}{r^{11}} + \frac{5B}{r^6} = 0$
$r^5 = \frac{2A}{B}$
So the answer is (c) $\left(\frac{2A}{B}\right)^{1/5}$ .

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