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MHT CET 2026 (15 May, Shift 1) · Potentiometer

Potentiometer question from MHT CET 2026 (15 May, Shift 1)

Q10MHT CET 2026 · 15 MAY · SHIFT 1Medium

Potentiometer

Potentiometer wire of length $1$ m is connected in series with $490\ \Omega$ resistance and $2$ V battery. If $0.2$ mV/cm is the potential gradient then the resistance of the potentiometer wire is

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Answer: (a)

$k = 0.2\ \text{mV/cm} = 0.02\ \text{V/m}$ , so p.d. across 1 m wire $= 0.02\ \text{V}$ .
$\frac{2r}{490 + r} = 0.02 \Rightarrow 1.98r = 9.8$
$r \approx 4.95\ \Omega \approx 4.9\ \Omega$ .
So the answer is (a) $4.9\ \Omega$ .

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