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JEE Main 2024 (6 Apr, Shift 2) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from JEE Main 2024 (6 Apr, Shift 2)

Q26JEE Main 2024 · 6 APR · SHIFT 2Easy

Excess Pressure: Drops & Bubbles

Pressure inside a soap bubble is greater than the pressure outside by an amount: (given: $R =$ Radius of bubble, $S =$ Surface tension of bubble)

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Answer: (b)

A soap bubble has two free surfaces (inner and outer), each giving $\frac{2S}{R}$ .
Total excess pressure $= \frac{2S}{R} + \frac{2S}{R} = \frac{4S}{R}$
So the answer is (b) $\frac{4S}{R}$ .

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