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JEE Main 2020 (3 Sep, Shift 1) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from JEE Main 2020 (3 Sep, Shift 1)

Q52JEE Main 2020 · 3 SEP · SHIFT 1Easy

Excess Pressure: Drops & Bubbles

Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere, respectively. The ratio of their volumes is:

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Answer: (b)

Excess pressures (outside 1 atm): $\Delta P_1 = 0.01$ atm, $\Delta P_2 = 0.02$ atm.
$\Delta P \propto \frac{1}{R} \Rightarrow \frac{R_1}{R_2} = \frac{0.02}{0.01} = 2$
$\frac{V_1}{V_2} = 2^3 = 8$
So the answer is (b) $8 : 1$ .

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