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JEE Main 2019 (8 Apr, Shift 1) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2019 (8 Apr, Shift 1)

Q59JEE Main 2019 · 8 APR · SHIFT 1Difficult

Transitions, Photon Emission & Excitation

Radiation coming from transitions n = 2 to n = 1 of hydrogen atoms fall on He+ ions in n = 1 and n = 2 states. The possible transition of helium ions as they absorb energy from the radiation is:

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Answer: (c)

  1. Photon from H (2→12 \to 1): E=13.6(1−14)=10.2 eVE = 13.6\left(1 - \frac{1}{4}\right) = 10.2\text{ eV}.
  2. He+^+ levels: En=−54.4n2E_n = -\frac{54.4}{n^2} eV, so E1=−54.4E_1 = -54.4, E2=−13.6E_2 = -13.6, E3=−6.04E_3 = -6.04, E4=−3.4E_4 = -3.4, E5=−2.18E_5 = -2.18 eV.
  3. From n=2n = 2: E4−E2=−3.4+13.6=10.2 eVE_4 - E_2 = -3.4 + 13.6 = 10.2\text{ eV}, an exact match.
  4. No other listed jump needs exactly 10.210.2 eV.
  5. So the answer is (c) n=2→n=4n = 2 \rightarrow n = 4.
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