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MHT CET 2024 (10 May, Shift 2) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2024 (10 May, Shift 2)

Q53MHT CET 2024 · 10 MAY · SHIFT 2Medium

Bohr Model: Orbits, Speed & Angular Momentum

Radius of first orbit in H -atom is ' $a_0$ ' Then, de-Broglie wavelength of electron in the third orbit is

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Answer: (b)

Bohr condition: $n\lambda = 2\pi r_n \Rightarrow \lambda = \frac{2\pi r_n}{n}$
$r_3 = 9a_0 \Rightarrow \lambda = \frac{2\pi\times9a_0}{3} = 6\pi a_0$
So the answer is (b) $6\pi a_0$ .

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