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MHT CET 2023 (11 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2023 (11 May, Shift 1)

Q99MHT CET 2023 · 11 MAY · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Radius of gyration of a thin uniform circular disc about the axis passing through its centre and perpendicular to its plane is KcK_c. Radius of gyration of the same disc about a diameter of the disc is KdK_d. The ratio Kc:KdK_c : K_d is

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Answer: (a)

  1. Kc2=R22K_c^2 = \frac{R^2}{2} (perpendicular axis), Kd2=R24K_d^2 = \frac{R^2}{4} (diameter).
  2. KcKd=2\frac{K_c}{K_d} = \sqrt{2}
  3. So the answer is (a) 2:1\sqrt{2} : 1.
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