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MHT CET 2024 (11 May, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2024 (11 May, Shift 1)

Q26MHT CET 2024 · 11 MAY · SHIFT 1Medium

Thermometry & Thermal Expansion

Rails of material of steel are laid with gaps to allow for thermal expansion. Each track is 10 m long, when laid at temperature 17∘C17^\circ\text{C}. The maximum temperature that can be reached is 45∘C45^\circ\text{C}. The gap to be kept between the two segments of railway track is

(α(\alphasteel =1.3×10−5/∘C)= 1.3 \times 10^{-5}/^\circ\text{C})

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Answer: (c)

  1. Gap == expansion of one segment: ΔL=LαΔT\Delta L=L\alpha\Delta T
  2. ΔL=10×1.3×10−5×(45−17)=3.64×10−3\Delta L=10\times1.3\times10^{-5}\times(45-17)=3.64\times10^{-3} m
  3. So the answer is (c) 3.64 mm.
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