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MHT CET 2024 (2 May, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2024 (2 May, Shift 1)

Q28MHT CET 2024 · 2 MAY · SHIFT 1Medium

Thermometry & Thermal Expansion

Railway track is made of steel segments separated by small gaps to allow for linear expansion. The segment of track is 10 m long when laid at temperature 17∘C17^\circ\text{C}. The maximum temperature that can be reached is 45∘C45^\circ\text{C}. Increase in length of the segment of railway track is ' xx ' ×10−5 m\times 10^{-5}\text{ m}. The value of ' xx ' is (α(\alphasteel =1.2×10−5/∘C)= 1.2 \times 10^{-5}/^\circ\text{C})

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Answer: (c)

  1. ΔL=LαΔT=10×1.2×10−5×28\Delta L=L\alpha\Delta T=10\times1.2\times10^{-5}\times28
  2. ΔL=336×10−5\Delta L=336\times10^{-5} m
  3. So x=336x=336, answer (c).
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